Base | Representation |
---|---|
bin | 100110111001011010000011… |
… | …0111101001000011010100111 |
3 | 1122212102102000212002011221011 |
4 | 1031302310012331020122213 |
5 | 324321121301123031312 |
6 | 3211401345504003051 |
7 | 132031623324212644 |
oct | 11562640675103247 |
9 | 1585372025064834 |
10 | 342141506455207 |
11 | 9a020441868618 |
12 | 32459396300487 |
13 | 118baa61c38134 |
14 | 606ba470d2dcb |
15 | 2984d4464bda7 |
hex | 1372d06f486a7 |
342141506455207 has 2 divisors, whose sum is σ = 342141506455208. Its totient is φ = 342141506455206.
The previous prime is 342141506455109. The next prime is 342141506455247. The reversal of 342141506455207 is 702554605141243.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 342141506455207 - 239 = 341591750641319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (342141506455247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171070753227603 + 171070753227604.
It is an arithmetic number, because the mean of its divisors is an integer number (171070753227604).
Almost surely, 2342141506455207 is an apocalyptic number.
342141506455207 is a deficient number, since it is larger than the sum of its proper divisors (1).
342141506455207 is an equidigital number, since it uses as much as digits as its factorization.
342141506455207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032000, while the sum is 49.
The spelling of 342141506455207 in words is "three hundred forty-two trillion, one hundred forty-one billion, five hundred six million, four hundred fifty-five thousand, two hundred seven".
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