Base | Representation |
---|---|
bin | 110001110010111011111… |
… | …111011111110111001101 |
3 | 110010010122102210011021212 |
4 | 301302323333133313031 |
5 | 422031122133440324 |
6 | 11140004324304205 |
7 | 502141026451055 |
oct | 61627377376715 |
9 | 13103572704255 |
10 | 3421947952589 |
11 | 10aa270455771 |
12 | 473243542065 |
13 | 1ba8c4298c2a |
14 | bb8a1d6c565 |
15 | 5e02cdd970e |
hex | 31cbbfdfdcd |
3421947952589 has 2 divisors, whose sum is σ = 3421947952590. Its totient is φ = 3421947952588.
The previous prime is 3421947952573. The next prime is 3421947952639. The reversal of 3421947952589 is 9852597491243.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3172377767689 + 249570184900 = 1781117^2 + 499570^2 .
It is a cyclic number.
It is not a de Polignac number, because 3421947952589 - 24 = 3421947952573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3421947951589) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710973976294 + 1710973976295.
It is an arithmetic number, because the mean of its divisors is an integer number (1710973976295).
Almost surely, 23421947952589 is an apocalyptic number.
It is an amenable number.
3421947952589 is a deficient number, since it is larger than the sum of its proper divisors (1).
3421947952589 is an equidigital number, since it uses as much as digits as its factorization.
3421947952589 is an evil number, because the sum of its binary digits is even.
The product of its digits is 195955200, while the sum is 68.
The spelling of 3421947952589 in words is "three trillion, four hundred twenty-one billion, nine hundred forty-seven million, nine hundred fifty-two thousand, five hundred eighty-nine".
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