Base | Representation |
---|---|
bin | 110001110100000110101… |
… | …011000111011110110111 |
3 | 110010020212202102112110022 |
4 | 301310012223013132313 |
5 | 422041203412313142 |
6 | 11140332523315355 |
7 | 502214052364034 |
oct | 61640653073667 |
9 | 13106782375408 |
10 | 3423200901047 |
11 | 10aa853736464 |
12 | 47353307bb5b |
13 | 1baa63a3b855 |
14 | bb98052238b |
15 | 5e0a2dd36d2 |
hex | 31d06ac77b7 |
3423200901047 has 2 divisors, whose sum is σ = 3423200901048. Its totient is φ = 3423200901046.
The previous prime is 3423200901019. The next prime is 3423200901149. The reversal of 3423200901047 is 7401090023243.
3423200901047 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3423200901047 - 210 = 3423200900023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3423200900998 and 3423200901016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3423200901017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1711600450523 + 1711600450524.
It is an arithmetic number, because the mean of its divisors is an integer number (1711600450524).
Almost surely, 23423200901047 is an apocalyptic number.
3423200901047 is a deficient number, since it is larger than the sum of its proper divisors (1).
3423200901047 is an equidigital number, since it uses as much as digits as its factorization.
3423200901047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 35.
The spelling of 3423200901047 in words is "three trillion, four hundred twenty-three billion, two hundred million, nine hundred one thousand, forty-seven".
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