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342335114969 is a prime number
BaseRepresentation
bin1001111101101001100…
…00110100111011011001
31012201121220220200210012
410332310300310323121
521102100242134334
6421133325331305
733506245315451
oct4766460647331
91181556820705
10342335114969
1112220227a821
125641b406b35
13263888cc4b3
14127d78bcd61
158d891a19ce
hex4fb4c34ed9

342335114969 has 2 divisors, whose sum is σ = 342335114970. Its totient is φ = 342335114968.

The previous prime is 342335114893. The next prime is 342335114971. The reversal of 342335114969 is 969411533243.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 172360316569 + 169974798400 = 415163^2 + 412280^2 .

It is an emirp because it is prime and its reverse (969411533243) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-342335114969 is a prime.

It is a super-2 number, since 2×3423351149692 (a number of 24 digits) contains 22 as substring.

Together with 342335114971, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (342335114369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171167557484 + 171167557485.

It is an arithmetic number, because the mean of its divisors is an integer number (171167557485).

Almost surely, 2342335114969 is an apocalyptic number.

It is an amenable number.

342335114969 is a deficient number, since it is larger than the sum of its proper divisors (1).

342335114969 is an equidigital number, since it uses as much as digits as its factorization.

342335114969 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2099520, while the sum is 50.

The spelling of 342335114969 in words is "three hundred forty-two billion, three hundred thirty-five million, one hundred fourteen thousand, nine hundred sixty-nine".