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34241313541 is a prime number
BaseRepresentation
bin11111111000111100…
…001111101100000101
310021101100001221202211
4133320330033230011
51030111234013131
623421422103421
72321350235311
oct377074175405
9107340057684
1034241313541
1113581368736
12677741ab71
1332c8ca7496
14192b856b41
15d561695b1
hex7f8f0fb05

34241313541 has 2 divisors, whose sum is σ = 34241313542. Its totient is φ = 34241313540.

The previous prime is 34241313529. The next prime is 34241313551. The reversal of 34241313541 is 14531314243.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27865291041 + 6376022500 = 166929^2 + 79850^2 .

It is an emirp because it is prime and its reverse (14531314243) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34241313541 - 223 = 34232924933 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34241313551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17120656770 + 17120656771.

It is an arithmetic number, because the mean of its divisors is an integer number (17120656771).

Almost surely, 234241313541 is an apocalyptic number.

It is an amenable number.

34241313541 is a deficient number, since it is larger than the sum of its proper divisors (1).

34241313541 is an equidigital number, since it uses as much as digits as its factorization.

34241313541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17280, while the sum is 31.

Adding to 34241313541 its reverse (14531314243), we get a palindrome (48772627784).

The spelling of 34241313541 in words is "thirty-four billion, two hundred forty-one million, three hundred thirteen thousand, five hundred forty-one".