Base | Representation |
---|---|
bin | 1111100100100011110100… |
… | …10000111010010111011001 |
3 | 11111020110101010201001001202 |
4 | 13302101322100322113121 |
5 | 13442003123304144213 |
6 | 200454201510523545 |
7 | 10132604022162362 |
oct | 762217220722731 |
9 | 144213333631052 |
10 | 34241530537433 |
11 | aa0182a34a32a |
12 | 3a102a33665b5 |
13 | 1614c6873114b |
14 | 86542834ab69 |
15 | 3e5a7a26cb58 |
hex | 1f247a43a5d9 |
34241530537433 has 2 divisors, whose sum is σ = 34241530537434. Its totient is φ = 34241530537432.
The previous prime is 34241530537391. The next prime is 34241530537451. The reversal of 34241530537433 is 33473503514243.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30261298054729 + 3980232482704 = 5501027^2 + 1995052^2 .
It is a cyclic number.
It is not a de Polignac number, because 34241530537433 - 220 = 34241529488857 is a prime.
It is not a weakly prime, because it can be changed into another prime (34241530737433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17120765268716 + 17120765268717.
It is an arithmetic number, because the mean of its divisors is an integer number (17120765268717).
Almost surely, 234241530537433 is an apocalyptic number.
It is an amenable number.
34241530537433 is a deficient number, since it is larger than the sum of its proper divisors (1).
34241530537433 is an equidigital number, since it uses as much as digits as its factorization.
34241530537433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5443200, while the sum is 47.
The spelling of 34241530537433 in words is "thirty-four trillion, two hundred forty-one billion, five hundred thirty million, five hundred thirty-seven thousand, four hundred thirty-three".
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