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3424249402447 is a prime number
BaseRepresentation
bin110001110101000101001…
…010110101010001001111
3110010100120211100220222111
4301311011022311101033
5422100330321334242
611141024540324451
7502252043451316
oct61650512652117
913110524326874
103424249402447
111100241577045
12473786243727
131baba002ac93
14bba3d89727d
155e114e95817
hex31d452b544f

3424249402447 has 2 divisors, whose sum is σ = 3424249402448. Its totient is φ = 3424249402446.

The previous prime is 3424249402373. The next prime is 3424249402489. The reversal of 3424249402447 is 7442049424243.

3424249402447 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3424249402447 - 27 = 3424249402319 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3424249402447.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3424249402547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1712124701223 + 1712124701224.

It is an arithmetic number, because the mean of its divisors is an integer number (1712124701224).

Almost surely, 23424249402447 is an apocalyptic number.

3424249402447 is a deficient number, since it is larger than the sum of its proper divisors (1).

3424249402447 is an equidigital number, since it uses as much as digits as its factorization.

3424249402447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6193152, while the sum is 49.

The spelling of 3424249402447 in words is "three trillion, four hundred twenty-four billion, two hundred forty-nine million, four hundred two thousand, four hundred forty-seven".