Base | Representation |
---|---|
bin | 1111100100100111001001… |
… | …00010100010110110011111 |
3 | 11111020121222101202012002111 |
4 | 13302103210202202312133 |
5 | 13442020301231411412 |
6 | 200455054442534451 |
7 | 10132666142404126 |
oct | 762234442426637 |
9 | 144217871665074 |
10 | 34243313544607 |
11 | aa02564857a82 |
12 | 3a10700507427 |
13 | 1615190c5178b |
14 | 86555707cabd |
15 | 3e5b31a6b2a7 |
hex | 1f24e48a2d9f |
34243313544607 has 2 divisors, whose sum is σ = 34243313544608. Its totient is φ = 34243313544606.
The previous prime is 34243313544589. The next prime is 34243313544611. The reversal of 34243313544607 is 70644531334243.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34243313544607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34243313544637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17121656772303 + 17121656772304.
It is an arithmetic number, because the mean of its divisors is an integer number (17121656772304).
Almost surely, 234243313544607 is an apocalyptic number.
34243313544607 is a deficient number, since it is larger than the sum of its proper divisors (1).
34243313544607 is an equidigital number, since it uses as much as digits as its factorization.
34243313544607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8709120, while the sum is 49.
The spelling of 34243313544607 in words is "thirty-four trillion, two hundred forty-three billion, three hundred thirteen million, five hundred forty-four thousand, six hundred seven".
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