Base | Representation |
---|---|
bin | 110001110101111010011… |
… | …111011101111010001111 |
3 | 110010102220011201101221012 |
4 | 301311322133131322033 |
5 | 422104143331113424 |
6 | 11141253414555435 |
7 | 502313155444646 |
oct | 61657237357217 |
9 | 13112804641835 |
10 | 3425144004239 |
11 | 1100660551671 |
12 | 473995968b7b |
13 | 1bacb3484559 |
14 | bbac660a35d |
15 | 5e1687a7b0e |
hex | 31d7a7dde8f |
3425144004239 has 2 divisors, whose sum is σ = 3425144004240. Its totient is φ = 3425144004238.
The previous prime is 3425144004223. The next prime is 3425144004319. The reversal of 3425144004239 is 9324004415243.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3425144004239 - 24 = 3425144004223 is a prime.
It is a super-2 number, since 2×34251440042392 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3425144004196 and 3425144004205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3425144034239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1712572002119 + 1712572002120.
It is an arithmetic number, because the mean of its divisors is an integer number (1712572002120).
Almost surely, 23425144004239 is an apocalyptic number.
3425144004239 is a deficient number, since it is larger than the sum of its proper divisors (1).
3425144004239 is an equidigital number, since it uses as much as digits as its factorization.
3425144004239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 41.
The spelling of 3425144004239 in words is "three trillion, four hundred twenty-five billion, one hundred forty-four million, four thousand, two hundred thirty-nine".
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