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342605531235161 is a prime number
BaseRepresentation
bin100110111100110010001000…
…0111111001100001101011001
31122221001202202112120100211102
41031321210100333030031121
5324401222111444011121
63212354450325241145
7132110301306603005
oct11571442077141531
91587052675510742
10342605531235161
119a18a20a7467a7
12325132b72631b5
1311922741ac004c
1460862a64ad705
152991e51cb590b
hex1379910fcc359

342605531235161 has 2 divisors, whose sum is σ = 342605531235162. Its totient is φ = 342605531235160.

The previous prime is 342605531235073. The next prime is 342605531235179. The reversal of 342605531235161 is 161532135506243.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 277230625259536 + 65374905975625 = 16650244^2 + 8085475^2 .

It is an emirp because it is prime and its reverse (161532135506243) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 342605531235161 - 210 = 342605531234137 is a prime.

It is not a weakly prime, because it can be changed into another prime (342605531235061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171302765617580 + 171302765617581.

It is an arithmetic number, because the mean of its divisors is an integer number (171302765617581).

Almost surely, 2342605531235161 is an apocalyptic number.

It is an amenable number.

342605531235161 is a deficient number, since it is larger than the sum of its proper divisors (1).

342605531235161 is an equidigital number, since it uses as much as digits as its factorization.

342605531235161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944000, while the sum is 47.

The spelling of 342605531235161 in words is "three hundred forty-two trillion, six hundred five billion, five hundred thirty-one million, two hundred thirty-five thousand, one hundred sixty-one".