Base | Representation |
---|---|
bin | 110001111010101111000… |
… | …100101000111011100111 |
3 | 110010221020222101201001122 |
4 | 301322233010220323213 |
5 | 422200244202144424 |
6 | 11143511234444155 |
7 | 502555361343452 |
oct | 61725704507347 |
9 | 13127228351048 |
10 | 3430321131239 |
11 | 1102877939822 |
12 | 47499b73365b |
13 | 1bb629c1c402 |
14 | bc058018499 |
15 | 5e36d04b45e |
hex | 31eaf128ee7 |
3430321131239 has 2 divisors, whose sum is σ = 3430321131240. Its totient is φ = 3430321131238.
The previous prime is 3430321131221. The next prime is 3430321131277. The reversal of 3430321131239 is 9321311230343.
3430321131239 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3430321131239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3430321131199 and 3430321131208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3430321134239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1715160565619 + 1715160565620.
It is an arithmetic number, because the mean of its divisors is an integer number (1715160565620).
Almost surely, 23430321131239 is an apocalyptic number.
3430321131239 is a deficient number, since it is larger than the sum of its proper divisors (1).
3430321131239 is an equidigital number, since it uses as much as digits as its factorization.
3430321131239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 35.
The spelling of 3430321131239 in words is "three trillion, four hundred thirty billion, three hundred twenty-one million, one hundred thirty-one thousand, two hundred thirty-nine".
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