Base | Representation |
---|---|
bin | 1111100110011000001011… |
… | …10111001011100010010011 |
3 | 11111110102121220001111011212 |
4 | 13303030011313023202103 |
5 | 13444014044022110103 |
6 | 200543012510130335 |
7 | 10140245103112325 |
oct | 763140567134223 |
9 | 144412556044155 |
10 | 34304002144403 |
11 | aa262779a8282 |
12 | 3a20418ab09ab |
13 | 161ab13259064 |
14 | 86847317d615 |
15 | 3e74d498d7d8 |
hex | 1f3305dcb893 |
34304002144403 has 2 divisors, whose sum is σ = 34304002144404. Its totient is φ = 34304002144402.
The previous prime is 34304002144337. The next prime is 34304002144409. The reversal of 34304002144403 is 30444120040343.
It is a strong prime.
It is an emirp because it is prime and its reverse (30444120040343) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34304002144403 - 210 = 34304002143379 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 34304002144403.
It is not a weakly prime, because it can be changed into another prime (34304002144409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17152001072201 + 17152001072202.
It is an arithmetic number, because the mean of its divisors is an integer number (17152001072202).
Almost surely, 234304002144403 is an apocalyptic number.
34304002144403 is a deficient number, since it is larger than the sum of its proper divisors (1).
34304002144403 is an equidigital number, since it uses as much as digits as its factorization.
34304002144403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 34304002144403 its reverse (30444120040343), we get a palindrome (64748122184746).
The spelling of 34304002144403 in words is "thirty-four trillion, three hundred four billion, two million, one hundred forty-four thousand, four hundred three".
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