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343100133441449 is a prime number
BaseRepresentation
bin100111000000011000011100…
…1100100110111111110101001
31122222211001102012212202010022
41032000300321210313332221
5324432323033130111244
63213414005251130225
7132161111103152426
oct11600607144677651
91588731365782108
10343100133441449
119a35aa497a895a
12325931305a3975
131195a285860c37
1460a21c6882d4d
15299ec4dab76ee
hex1380c39937fa9

343100133441449 has 2 divisors, whose sum is σ = 343100133441450. Its totient is φ = 343100133441448.

The previous prime is 343100133441229. The next prime is 343100133441451. The reversal of 343100133441449 is 944144331001343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 254459923240000 + 88640210201449 = 15951800^2 + 9414893^2 .

It is a cyclic number.

It is not a de Polignac number, because 343100133441449 - 224 = 343100116664233 is a prime.

It is a super-2 number, since 2×3431001334414492 (a number of 30 digits) contains 22 as substring.

Together with 343100133441451, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (343100133441479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171550066720724 + 171550066720725.

It is an arithmetic number, because the mean of its divisors is an integer number (171550066720725).

Almost surely, 2343100133441449 is an apocalyptic number.

It is an amenable number.

343100133441449 is a deficient number, since it is larger than the sum of its proper divisors (1).

343100133441449 is an equidigital number, since it uses as much as digits as its factorization.

343100133441449 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 746496, while the sum is 44.

The spelling of 343100133441449 in words is "three hundred forty-three trillion, one hundred billion, one hundred thirty-three million, four hundred forty-one thousand, four hundred forty-nine".