Base | Representation |
---|---|
bin | 100111000000100110011010… |
… | …0011001101101110011000001 |
3 | 1122222220220210102200212220011 |
4 | 1032001030310121231303001 |
5 | 324433320432004314103 |
6 | 3213435444054544521 |
7 | 132163222014464026 |
oct | 11601146431556301 |
9 | 1588826712625804 |
10 | 343130111401153 |
11 | 9a37173255876a |
12 | 32598ab8068141 |
13 | 119600524aa02b |
14 | 60a382bdd154d |
15 | 29a09057dad6d |
hex | 138133466dcc1 |
343130111401153 has 2 divisors, whose sum is σ = 343130111401154. Its totient is φ = 343130111401152.
The previous prime is 343130111401111. The next prime is 343130111401213. The reversal of 343130111401153 is 351104111031343.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 294670594704784 + 48459516696369 = 17165972^2 + 6961287^2 .
It is a cyclic number.
It is not a de Polignac number, because 343130111401153 - 29 = 343130111400641 is a prime.
It is not a weakly prime, because it can be changed into another prime (343100111401153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171565055700576 + 171565055700577.
It is an arithmetic number, because the mean of its divisors is an integer number (171565055700577).
Almost surely, 2343130111401153 is an apocalyptic number.
It is an amenable number.
343130111401153 is a deficient number, since it is larger than the sum of its proper divisors (1).
343130111401153 is an equidigital number, since it uses as much as digits as its factorization.
343130111401153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 343130111401153 its reverse (351104111031343), we get a palindrome (694234222432496).
The spelling of 343130111401153 in words is "three hundred forty-three trillion, one hundred thirty billion, one hundred eleven million, four hundred one thousand, one hundred fifty-three".
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