Base | Representation |
---|---|
bin | 100111000000101000010010… |
… | …0001100010111010011110011 |
3 | 1122222221022011210202002010002 |
4 | 1032001100210030113103303 |
5 | 324433402201403324021 |
6 | 3213441351210300215 |
7 | 132163423504624625 |
oct | 11601204414272363 |
9 | 1588838153662102 |
10 | 343134134433011 |
11 | 9a373407443089 |
12 | 3259983b42766b |
13 | 11960543b03b5c |
14 | 60a3ad041cc15 |
15 | 29a0a8dab050b |
hex | 13814243174f3 |
343134134433011 has 2 divisors, whose sum is σ = 343134134433012. Its totient is φ = 343134134433010.
The previous prime is 343134134432977. The next prime is 343134134433143. The reversal of 343134134433011 is 110334431431343.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-343134134433011 is a prime.
It is a super-2 number, since 2×3431341344330112 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (343134134439011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171567067216505 + 171567067216506.
It is an arithmetic number, because the mean of its divisors is an integer number (171567067216506).
Almost surely, 2343134134433011 is an apocalyptic number.
343134134433011 is a deficient number, since it is larger than the sum of its proper divisors (1).
343134134433011 is an equidigital number, since it uses as much as digits as its factorization.
343134134433011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 38.
Adding to 343134134433011 its reverse (110334431431343), we get a palindrome (453468565864354).
The spelling of 343134134433011 in words is "three hundred forty-three trillion, one hundred thirty-four billion, one hundred thirty-four million, four hundred thirty-three thousand, eleven".
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