Base | Representation |
---|---|
bin | 100111000001001011101000… |
… | …0101010000001101111000011 |
3 | 1200000012120002221211222202212 |
4 | 1032002113100222001233003 |
5 | 324441123131314143042 |
6 | 3213540303344132335 |
7 | 132202051540266062 |
oct | 11602272052015703 |
9 | 1600176087758685 |
10 | 343210042334147 |
11 | 9a3a261a48077a |
12 | 325b04a49070ab |
13 | 1196775020bba1 |
14 | 60a765190c1d9 |
15 | 29a2a32bb5482 |
hex | 13825d0a81bc3 |
343210042334147 has 2 divisors, whose sum is σ = 343210042334148. Its totient is φ = 343210042334146.
The previous prime is 343210042334099. The next prime is 343210042334149. The reversal of 343210042334147 is 741433240012343.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-343210042334147 is a prime.
Together with 343210042334149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (343210042334149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171605021167073 + 171605021167074.
It is an arithmetic number, because the mean of its divisors is an integer number (171605021167074).
Almost surely, 2343210042334147 is an apocalyptic number.
343210042334147 is a deficient number, since it is larger than the sum of its proper divisors (1).
343210042334147 is an equidigital number, since it uses as much as digits as its factorization.
343210042334147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 580608, while the sum is 41.
The spelling of 343210042334147 in words is "three hundred forty-three trillion, two hundred ten billion, forty-two million, three hundred thirty-four thousand, one hundred forty-seven".
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