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343210042334147 is a prime number
BaseRepresentation
bin100111000001001011101000…
…0101010000001101111000011
31200000012120002221211222202212
41032002113100222001233003
5324441123131314143042
63213540303344132335
7132202051540266062
oct11602272052015703
91600176087758685
10343210042334147
119a3a261a48077a
12325b04a49070ab
131196775020bba1
1460a765190c1d9
1529a2a32bb5482
hex13825d0a81bc3

343210042334147 has 2 divisors, whose sum is σ = 343210042334148. Its totient is φ = 343210042334146.

The previous prime is 343210042334099. The next prime is 343210042334149. The reversal of 343210042334147 is 741433240012343.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-343210042334147 is a prime.

Together with 343210042334149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (343210042334149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171605021167073 + 171605021167074.

It is an arithmetic number, because the mean of its divisors is an integer number (171605021167074).

Almost surely, 2343210042334147 is an apocalyptic number.

343210042334147 is a deficient number, since it is larger than the sum of its proper divisors (1).

343210042334147 is an equidigital number, since it uses as much as digits as its factorization.

343210042334147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 580608, while the sum is 41.

The spelling of 343210042334147 in words is "three hundred forty-three trillion, two hundred ten billion, forty-two million, three hundred thirty-four thousand, one hundred forty-seven".