Base | Representation |
---|---|
bin | 1111100111001010111001… |
… | …11000111000001110000111 |
3 | 11111120000220120212001002211 |
4 | 13303211130320320032013 |
5 | 13444440330343324033 |
6 | 201003314504444251 |
7 | 10142230635135034 |
oct | 763453470701607 |
9 | 144500816761084 |
10 | 34331232011143 |
11 | aa36880503181 |
12 | 3a25758179687 |
13 | 1620562750342 |
14 | 8698d773a38b |
15 | 3e807a2cc2cd |
hex | 1f395ce38387 |
34331232011143 has 32 divisors (see below), whose sum is σ = 35642897136000. Its totient is φ = 33044410736640.
The previous prime is 34331232011039. The next prime is 34331232011149. The reversal of 34331232011143 is 34111023213343.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34331232011143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34331232011149) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4448775721 + ... + 4448783437.
It is an arithmetic number, because the mean of its divisors is an integer number (1113840535500).
Almost surely, 234331232011143 is an apocalyptic number.
34331232011143 is a deficient number, since it is larger than the sum of its proper divisors (1311665124857).
34331232011143 is a wasteful number, since it uses less digits than its factorization.
34331232011143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11227.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 34331232011143 its reverse (34111023213343), we get a palindrome (68442255224486).
The spelling of 34331232011143 in words is "thirty-four trillion, three hundred thirty-one billion, two hundred thirty-two million, eleven thousand, one hundred forty-three".
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