Search a number
-
+
343313004114 = 232113168787121
BaseRepresentation
bin1001111111011110000…
…11001011011001010010
31012211011001222121111200
410333233003023121102
521111101112112424
6421414341052030
733542421246303
oct4775703133122
91184131877450
10343313004114
11122664271373
12566529b7016
13264b3397522
141288b7127aa
158de4e668c9
hex4fef0cb652

343313004114 has 24 divisors (see below), whose sum is σ = 750427544412. Its totient is φ = 113424944640.

The previous prime is 343313004109. The next prime is 343313004121. The reversal of 343313004114 is 411400313343.

343313004114 is a `hidden beast` number, since 343 + 3 + 1 + 300 + 4 + 1 + 14 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 294487472889 + 48825531225 = 542667^2 + 220965^2 .

It is a super-3 number, since 3×3433130041143 (a number of 36 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 84391527 + ... + 84395594.

Almost surely, 2343313004114 is an apocalyptic number.

343313004114 is an abundant number, since it is smaller than the sum of its proper divisors (407114540298).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

343313004114 is a wasteful number, since it uses less digits than its factorization.

343313004114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 168787242 (or 168787239 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 343313004114 its reverse (411400313343), we get a palindrome (754713317457).

The spelling of 343313004114 in words is "three hundred forty-three billion, three hundred thirteen million, four thousand, one hundred fourteen".

Divisors: 1 2 3 6 9 18 113 226 339 678 1017 2034 168787121 337574242 506361363 1012722726 1519084089 3038168178 19072944673 38145889346 57218834019 114437668038 171656502057 343313004114