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343313004121 is a prime number
BaseRepresentation
bin1001111111011110000…
…11001011011001011001
31012211011001222121111221
410333233003023121121
521111101112112441
6421414341052041
733542421246313
oct4775703133131
91184131877457
10343313004121
1112266427137a
12566529b7021
13264b3397529
141288b7127b3
158de4e668d1
hex4fef0cb659

343313004121 has 2 divisors, whose sum is σ = 343313004122. Its totient is φ = 343313004120.

The previous prime is 343313004109. The next prime is 343313004131. The reversal of 343313004121 is 121400313343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 340349726025 + 2963278096 = 583395^2 + 54436^2 .

It is a cyclic number.

It is not a de Polignac number, because 343313004121 - 29 = 343313003609 is a prime.

It is not a weakly prime, because it can be changed into another prime (343313004131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171656502060 + 171656502061.

It is an arithmetic number, because the mean of its divisors is an integer number (171656502061).

Almost surely, 2343313004121 is an apocalyptic number.

It is an amenable number.

343313004121 is a deficient number, since it is larger than the sum of its proper divisors (1).

343313004121 is an equidigital number, since it uses as much as digits as its factorization.

343313004121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 343313004121 its reverse (121400313343), we get a palindrome (464713317464).

The spelling of 343313004121 in words is "three hundred forty-three billion, three hundred thirteen million, four thousand, one hundred twenty-one".