Base | Representation |
---|---|
bin | 100111000010101101011101… |
… | …0011001100111010001111111 |
3 | 1200000221122100210102112101212 |
4 | 1032011122322121213101333 |
5 | 330003043402304031424 |
6 | 3214221005355355035 |
7 | 132223166526633563 |
oct | 11605327231472177 |
9 | 1600848323375355 |
10 | 343420122330239 |
11 | 9a473724125159 |
12 | 32625154152a7b |
13 | 119814bc976b96 |
14 | 60b38a06176a3 |
15 | 29a822b04a10e |
hex | 13856ba66747f |
343420122330239 has 2 divisors, whose sum is σ = 343420122330240. Its totient is φ = 343420122330238.
The previous prime is 343420122330227. The next prime is 343420122330247. The reversal of 343420122330239 is 932033221024343.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 343420122330239 - 244 = 325827936285823 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 343420122330196 and 343420122330205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (343420122330209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171710061165119 + 171710061165120.
It is an arithmetic number, because the mean of its divisors is an integer number (171710061165120).
Almost surely, 2343420122330239 is an apocalyptic number.
343420122330239 is a deficient number, since it is larger than the sum of its proper divisors (1).
343420122330239 is an equidigital number, since it uses as much as digits as its factorization.
343420122330239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 41.
The spelling of 343420122330239 in words is "three hundred forty-three trillion, four hundred twenty billion, one hundred twenty-two million, three hundred thirty thousand, two hundred thirty-nine".
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