Base | Representation |
---|---|
bin | 100111000010101101100110… |
… | …0010110001001100100110111 |
3 | 1200000221200010202222001222001 |
4 | 1032011123030112021210313 |
5 | 330003100011343141043 |
6 | 3214221055312520131 |
7 | 132223210144040206 |
oct | 11605331426114467 |
9 | 1600850122861861 |
10 | 343420423412023 |
11 | 9a473869078381 |
12 | 32625218b50047 |
13 | 1198153a163199 |
14 | 60b38cc5cd23d |
15 | 29a82476be74d |
hex | 13856cc589937 |
343420423412023 has 2 divisors, whose sum is σ = 343420423412024. Its totient is φ = 343420423412022.
The previous prime is 343420423411997. The next prime is 343420423412159. The reversal of 343420423412023 is 320214324024343.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 343420423412023 - 213 = 343420423403831 is a prime.
It is a super-2 number, since 2×3434204234120232 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (343420423412623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171710211706011 + 171710211706012.
It is an arithmetic number, because the mean of its divisors is an integer number (171710211706012).
Almost surely, 2343420423412023 is an apocalyptic number.
343420423412023 is a deficient number, since it is larger than the sum of its proper divisors (1).
343420423412023 is an equidigital number, since it uses as much as digits as its factorization.
343420423412023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 331776, while the sum is 37.
Adding to 343420423412023 its reverse (320214324024343), we get a palindrome (663634747436366).
The spelling of 343420423412023 in words is "three hundred forty-three trillion, four hundred twenty billion, four hundred twenty-three million, four hundred twelve thousand, twenty-three".
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