Base | Representation |
---|---|
bin | 1001111111101011000… |
… | …00011100101100010001 |
3 | 1012211102121211122222221 |
4 | 10333311200130230101 |
5 | 21111311330343213 |
6 | 421433211101041 |
7 | 33545205141523 |
oct | 4776540345421 |
9 | 1184377748887 |
10 | 343421340433 |
11 | 12270a437016 |
12 | 56683141781 |
13 | 264cc969562 |
14 | 1289bc73a13 |
15 | 8dee71638d |
hex | 4ff581cb11 |
343421340433 has 2 divisors, whose sum is σ = 343421340434. Its totient is φ = 343421340432.
The previous prime is 343421340419. The next prime is 343421340469. The reversal of 343421340433 is 334043124343.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 340755890049 + 2665450384 = 583743^2 + 51628^2 .
It is an emirp because it is prime and its reverse (334043124343) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 343421340433 - 217 = 343421209361 is a prime.
It is not a weakly prime, because it can be changed into another prime (343421340473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171710670216 + 171710670217.
It is an arithmetic number, because the mean of its divisors is an integer number (171710670217).
Almost surely, 2343421340433 is an apocalyptic number.
It is an amenable number.
343421340433 is a deficient number, since it is larger than the sum of its proper divisors (1).
343421340433 is an equidigital number, since it uses as much as digits as its factorization.
343421340433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 34.
Adding to 343421340433 its reverse (334043124343), we get a palindrome (677464464776).
The spelling of 343421340433 in words is "three hundred forty-three billion, four hundred twenty-one million, three hundred forty thousand, four hundred thirty-three".
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