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34343305445021 is a prime number
BaseRepresentation
bin1111100111100001011001…
…00001010111111010011101
311111121012002000011000210112
413303300230201113322131
514000140042143220041
6201013032520215405
710143136060466516
oct763605441277235
9144535060130715
1034343305445021
11aa40a06660801
123a27b6760a565
131621737b86661
1486a320dd1a0d
153e8535205deb
hex1f3c2c857e9d

34343305445021 has 2 divisors, whose sum is σ = 34343305445022. Its totient is φ = 34343305445020.

The previous prime is 34343305444999. The next prime is 34343305445039. The reversal of 34343305445021 is 12054450334343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31457078212921 + 2886227232100 = 5608661^2 + 1698890^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34343305445021 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 34343305445021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34343305445051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17171652722510 + 17171652722511.

It is an arithmetic number, because the mean of its divisors is an integer number (17171652722511).

Almost surely, 234343305445021 is an apocalyptic number.

It is an amenable number.

34343305445021 is a deficient number, since it is larger than the sum of its proper divisors (1).

34343305445021 is an equidigital number, since it uses as much as digits as its factorization.

34343305445021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 41.

Adding to 34343305445021 its reverse (12054450334343), we get a palindrome (46397755779364).

The spelling of 34343305445021 in words is "thirty-four trillion, three hundred forty-three billion, three hundred five million, four hundred forty-five thousand, twenty-one".