Base | Representation |
---|---|
bin | 110001111110100011100… |
… | …100100001011111000111 |
3 | 110011022211212000211120201 |
4 | 301332203210201133013 |
5 | 422232144310130210 |
6 | 11145430250511331 |
7 | 503062130635621 |
oct | 61764344413707 |
9 | 13138755024521 |
10 | 3434423130055 |
11 | 110459235a195 |
12 | 475745435547 |
13 | 1bbb31a04348 |
14 | bc326b1dc11 |
15 | 5e50d21d53a |
hex | 31fa39217c7 |
3434423130055 has 32 divisors (see below), whose sum is σ = 4592297410560. Its totient is φ = 2455603328640.
The previous prime is 3434423130049. The next prime is 3434423130121. The reversal of 3434423130055 is 5500313244343.
It is a happy number.
It is not a de Polignac number, because 3434423130055 - 25 = 3434423130023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3434423129996 and 3434423130023.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16506487 + ... + 16713256.
It is an arithmetic number, because the mean of its divisors is an integer number (143509294080).
Almost surely, 23434423130055 is an apocalyptic number.
3434423130055 is a deficient number, since it is larger than the sum of its proper divisors (1157874280505).
3434423130055 is a wasteful number, since it uses less digits than its factorization.
3434423130055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33219831.
The product of its (nonzero) digits is 259200, while the sum is 37.
Adding to 3434423130055 its reverse (5500313244343), we get a palindrome (8934736374398).
The spelling of 3434423130055 in words is "three trillion, four hundred thirty-four billion, four hundred twenty-three million, one hundred thirty thousand, fifty-five".
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