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34345500433 is a prime number
BaseRepresentation
bin11111111111001001…
…101011111100010001
310021122121010012022121
4133333021223330101
51030314422003213
623440023134241
72324053636216
oct377711537421
9107577105277
1034345500433
1113625159902
1267a62a4381
13331475592a
14193b617b0d
15d6039988d
hex7ff26bf11

34345500433 has 2 divisors, whose sum is σ = 34345500434. Its totient is φ = 34345500432.

The previous prime is 34345500407. The next prime is 34345500443. The reversal of 34345500433 is 33400554343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29047407489 + 5298092944 = 170433^2 + 72788^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34345500433 is a prime.

It is a super-2 number, since 2×343455004332 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (34345500443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17172750216 + 17172750217.

It is an arithmetic number, because the mean of its divisors is an integer number (17172750217).

Almost surely, 234345500433 is an apocalyptic number.

It is an amenable number.

34345500433 is a deficient number, since it is larger than the sum of its proper divisors (1).

34345500433 is an equidigital number, since it uses as much as digits as its factorization.

34345500433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 34.

The spelling of 34345500433 in words is "thirty-four billion, three hundred forty-five million, five hundred thousand, four hundred thirty-three".