Base | Representation |
---|---|
bin | 11111111111001001… |
… | …101011111100010001 |
3 | 10021122121010012022121 |
4 | 133333021223330101 |
5 | 1030314422003213 |
6 | 23440023134241 |
7 | 2324053636216 |
oct | 377711537421 |
9 | 107577105277 |
10 | 34345500433 |
11 | 13625159902 |
12 | 67a62a4381 |
13 | 331475592a |
14 | 193b617b0d |
15 | d6039988d |
hex | 7ff26bf11 |
34345500433 has 2 divisors, whose sum is σ = 34345500434. Its totient is φ = 34345500432.
The previous prime is 34345500407. The next prime is 34345500443. The reversal of 34345500433 is 33400554343.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29047407489 + 5298092944 = 170433^2 + 72788^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34345500433 is a prime.
It is a super-2 number, since 2×343455004332 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (34345500443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17172750216 + 17172750217.
It is an arithmetic number, because the mean of its divisors is an integer number (17172750217).
Almost surely, 234345500433 is an apocalyptic number.
It is an amenable number.
34345500433 is a deficient number, since it is larger than the sum of its proper divisors (1).
34345500433 is an equidigital number, since it uses as much as digits as its factorization.
34345500433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 34.
The spelling of 34345500433 in words is "thirty-four billion, three hundred forty-five million, five hundred thousand, four hundred thirty-three".
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