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34347250373 is a prime number
BaseRepresentation
bin11111111111010000…
…010111001011000101
310021122201102002210012
4133333100113023011
51030320344002443
623440124440005
72324104545122
oct377720271305
9107581362705
1034347250373
1113626144637
1267a69a9005
133314c192b7
14193b951749
15d605e3118
hex7ff4172c5

34347250373 has 2 divisors, whose sum is σ = 34347250374. Its totient is φ = 34347250372.

The previous prime is 34347250337. The next prime is 34347250387. The reversal of 34347250373 is 37305274343.

Together with previous prime (34347250337) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17737711489 + 16609538884 = 133183^2 + 128878^2 .

It is a cyclic number.

It is not a de Polignac number, because 34347250373 - 28 = 34347250117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 34347250373.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34347250303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17173625186 + 17173625187.

It is an arithmetic number, because the mean of its divisors is an integer number (17173625187).

Almost surely, 234347250373 is an apocalyptic number.

It is an amenable number.

34347250373 is a deficient number, since it is larger than the sum of its proper divisors (1).

34347250373 is an equidigital number, since it uses as much as digits as its factorization.

34347250373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 635040, while the sum is 41.

The spelling of 34347250373 in words is "thirty-four billion, three hundred forty-seven million, two hundred fifty thousand, three hundred seventy-three".