Base | Representation |
---|---|
bin | 110001111110110110011… |
… | …101101101110001111101 |
3 | 110011100122221111012202121 |
4 | 301332312131231301331 |
5 | 422233321432100014 |
6 | 11145521532522541 |
7 | 503103030145666 |
oct | 61766635556175 |
9 | 13140587435677 |
10 | 3434740112509 |
11 | 1104735282862 |
12 | 475813620451 |
13 | 1bbb82599c24 |
14 | bc356c7436d |
15 | 5e52ae84124 |
hex | 31fb676dc7d |
3434740112509 has 2 divisors, whose sum is σ = 3434740112510. Its totient is φ = 3434740112508.
The previous prime is 3434740112423. The next prime is 3434740112519. The reversal of 3434740112509 is 9052110474343.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1937413448100 + 1497326664409 = 1391910^2 + 1223653^2 .
It is a cyclic number.
It is not a de Polignac number, because 3434740112509 - 233 = 3426150177917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3434740112519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1717370056254 + 1717370056255.
It is an arithmetic number, because the mean of its divisors is an integer number (1717370056255).
Almost surely, 23434740112509 is an apocalyptic number.
It is an amenable number.
3434740112509 is a deficient number, since it is larger than the sum of its proper divisors (1).
3434740112509 is an equidigital number, since it uses as much as digits as its factorization.
3434740112509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 3434740112509 in words is "three trillion, four hundred thirty-four billion, seven hundred forty million, one hundred twelve thousand, five hundred nine".
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