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34352154020153 is a prime number
BaseRepresentation
bin1111100111110001110111…
…11100000000100100111001
311111122000220200022012221102
413303320323330000210321
514000311202412121103
6201021054532021145
710143601254234614
oct763707374004471
9144560820265842
1034352154020153
11aa44737427212
123a29816a617b5
131622518159328
1486a92026b17b
153e88a1e70e88
hex1f3e3bf00939

34352154020153 has 2 divisors, whose sum is σ = 34352154020154. Its totient is φ = 34352154020152.

The previous prime is 34352154020141. The next prime is 34352154020179. The reversal of 34352154020153 is 35102045125343.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33675412514704 + 676741505449 = 5803052^2 + 822643^2 .

It is a cyclic number.

It is not a de Polignac number, because 34352154020153 - 26 = 34352154020089 is a prime.

It is not a weakly prime, because it can be changed into another prime (34352154520153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17176077010076 + 17176077010077.

It is an arithmetic number, because the mean of its divisors is an integer number (17176077010077).

Almost surely, 234352154020153 is an apocalyptic number.

It is an amenable number.

34352154020153 is a deficient number, since it is larger than the sum of its proper divisors (1).

34352154020153 is an equidigital number, since it uses as much as digits as its factorization.

34352154020153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 34352154020153 its reverse (35102045125343), we get a palindrome (69454199145496).

The spelling of 34352154020153 in words is "thirty-four trillion, three hundred fifty-two billion, one hundred fifty-four million, twenty thousand, one hundred fifty-three".