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3438404048197 is a prime number
BaseRepresentation
bin110010000010010000110…
…110100001010101000101
3110011201010021211102122101
4302002100312201111011
5422313322414020242
611151325255432101
7503262600116146
oct62022066412505
913151107742571
103438404048197
11110624549a988
12476476685631
131bc3176a4501
14bc5c3707acd
155e6929749b7
hex32090da1545

3438404048197 has 2 divisors, whose sum is σ = 3438404048198. Its totient is φ = 3438404048196.

The previous prime is 3438404048113. The next prime is 3438404048357. The reversal of 3438404048197 is 7918404048343.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3339807420196 + 98596628001 = 1827514^2 + 314001^2 .

It is a cyclic number.

It is not a de Polignac number, because 3438404048197 - 227 = 3438269830469 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3438404648197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1719202024098 + 1719202024099.

It is an arithmetic number, because the mean of its divisors is an integer number (1719202024099).

Almost surely, 23438404048197 is an apocalyptic number.

It is an amenable number.

3438404048197 is a deficient number, since it is larger than the sum of its proper divisors (1).

3438404048197 is an equidigital number, since it uses as much as digits as its factorization.

3438404048197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9289728, while the sum is 55.

The spelling of 3438404048197 in words is "three trillion, four hundred thirty-eight billion, four hundred four million, forty-eight thousand, one hundred ninety-seven".