Base | Representation |
---|---|
bin | 1111101001001101101100… |
… | …10001111111011110110111 |
3 | 11111210202011021201122011101 |
4 | 13310212312101333132313 |
5 | 14002113133004242242 |
6 | 201055450350350531 |
7 | 10150265013562651 |
oct | 764466621773667 |
9 | 144722137648141 |
10 | 34401451243447 |
11 | aa63634423772 |
12 | 3a372944bb447 |
13 | 1627073426b42 |
14 | 86d0794dd6d1 |
15 | 3e9cd9c959b7 |
hex | 1f49b647f7b7 |
34401451243447 has 2 divisors, whose sum is σ = 34401451243448. Its totient is φ = 34401451243446.
The previous prime is 34401451243219. The next prime is 34401451243487. The reversal of 34401451243447 is 74434215410443.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34401451243447 is a prime.
It is a super-2 number, since 2×344014512434472 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34401451243397 and 34401451243406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34401451243487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17200725621723 + 17200725621724.
It is an arithmetic number, because the mean of its divisors is an integer number (17200725621724).
Almost surely, 234401451243447 is an apocalyptic number.
34401451243447 is a deficient number, since it is larger than the sum of its proper divisors (1).
34401451243447 is an equidigital number, since it uses as much as digits as its factorization.
34401451243447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2580480, while the sum is 46.
The spelling of 34401451243447 in words is "thirty-four trillion, four hundred one billion, four hundred fifty-one million, two hundred forty-three thousand, four hundred forty-seven".
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