Search a number
-
+
34401468214397 is a prime number
BaseRepresentation
bin1111101001001101101110…
…10010101110110001111101
311111210202012110122211221002
413310212313102232301331
514002113201330330042
6201055452154220045
710150265311044644
oct764466722566175
9144722173584832
1034401468214397
11aa63642a65249
123a3729a124625
131627076ab961b
1486d07b87a35b
153e9cdb4e9132
hex1f49b74aec7d

34401468214397 has 2 divisors, whose sum is σ = 34401468214398. Its totient is φ = 34401468214396.

The previous prime is 34401468214367. The next prime is 34401468214411. The reversal of 34401468214397 is 79341286410443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20874563939161 + 13526904275236 = 4568869^2 + 3677894^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34401468214397 is a prime.

It is a super-2 number, since 2×344014682143972 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34401468214307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17200734107198 + 17200734107199.

It is an arithmetic number, because the mean of its divisors is an integer number (17200734107199).

Almost surely, 234401468214397 is an apocalyptic number.

It is an amenable number.

34401468214397 is a deficient number, since it is larger than the sum of its proper divisors (1).

34401468214397 is an equidigital number, since it uses as much as digits as its factorization.

34401468214397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13934592, while the sum is 56.

The spelling of 34401468214397 in words is "thirty-four trillion, four hundred one billion, four hundred sixty-eight million, two hundred fourteen thousand, three hundred ninety-seven".