Base | Representation |
---|---|
bin | 1111101001010101010010… |
… | …11110001110010000110111 |
3 | 11111211010200122002122200012 |
4 | 13310222221132032100313 |
5 | 14002200012004010312 |
6 | 201101403300410435 |
7 | 10150501065603035 |
oct | 764525136162067 |
9 | 144733618078605 |
10 | 34405531313207 |
11 | aa6533852654a |
12 | 3a380329a6a1b |
13 | 16275738015c2 |
14 | 86d345337555 |
15 | 3e9e78085322 |
hex | 1f4aa978e437 |
34405531313207 has 2 divisors, whose sum is σ = 34405531313208. Its totient is φ = 34405531313206.
The previous prime is 34405531313171. The next prime is 34405531313249. The reversal of 34405531313207 is 70231313550443.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34405531313207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34405531313287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17202765656603 + 17202765656604.
It is an arithmetic number, because the mean of its divisors is an integer number (17202765656604).
Almost surely, 234405531313207 is an apocalyptic number.
34405531313207 is a deficient number, since it is larger than the sum of its proper divisors (1).
34405531313207 is an equidigital number, since it uses as much as digits as its factorization.
34405531313207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 453600, while the sum is 41.
The spelling of 34405531313207 in words is "thirty-four trillion, four hundred five billion, five hundred thirty-one million, three hundred thirteen thousand, two hundred seven".
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