Base | Representation |
---|---|
bin | 110010000100101100100… |
… | …100011100000111111101 |
3 | 110011221212100201110211212 |
4 | 302010230210130013331 |
5 | 422334200214211411 |
6 | 11152440422454205 |
7 | 503414412054116 |
oct | 62045444340775 |
9 | 13157770643755 |
10 | 3441016553981 |
11 | 1107366157176 |
12 | 476a85594365 |
13 | 1bc642a05716 |
14 | bc79068320d |
15 | 5e796ec568b |
hex | 3212c91c1fd |
3441016553981 has 2 divisors, whose sum is σ = 3441016553982. Its totient is φ = 3441016553980.
The previous prime is 3441016553959. The next prime is 3441016554071. The reversal of 3441016553981 is 1893556101443.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3138687029956 + 302329524025 = 1771634^2 + 549845^2 .
It is a cyclic number.
It is not a de Polignac number, because 3441016553981 - 210 = 3441016552957 is a prime.
It is a super-2 number, since 2×34410165539812 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3441016555981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1720508276990 + 1720508276991.
It is an arithmetic number, because the mean of its divisors is an integer number (1720508276991).
Almost surely, 23441016553981 is an apocalyptic number.
It is an amenable number.
3441016553981 is a deficient number, since it is larger than the sum of its proper divisors (1).
3441016553981 is an equidigital number, since it uses as much as digits as its factorization.
3441016553981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1555200, while the sum is 50.
The spelling of 3441016553981 in words is "three trillion, four hundred forty-one billion, sixteen million, five hundred fifty-three thousand, nine hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •