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3441016553981 is a prime number
BaseRepresentation
bin110010000100101100100…
…100011100000111111101
3110011221212100201110211212
4302010230210130013331
5422334200214211411
611152440422454205
7503414412054116
oct62045444340775
913157770643755
103441016553981
111107366157176
12476a85594365
131bc642a05716
14bc79068320d
155e796ec568b
hex3212c91c1fd

3441016553981 has 2 divisors, whose sum is σ = 3441016553982. Its totient is φ = 3441016553980.

The previous prime is 3441016553959. The next prime is 3441016554071. The reversal of 3441016553981 is 1893556101443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3138687029956 + 302329524025 = 1771634^2 + 549845^2 .

It is a cyclic number.

It is not a de Polignac number, because 3441016553981 - 210 = 3441016552957 is a prime.

It is a super-2 number, since 2×34410165539812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3441016555981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1720508276990 + 1720508276991.

It is an arithmetic number, because the mean of its divisors is an integer number (1720508276991).

Almost surely, 23441016553981 is an apocalyptic number.

It is an amenable number.

3441016553981 is a deficient number, since it is larger than the sum of its proper divisors (1).

3441016553981 is an equidigital number, since it uses as much as digits as its factorization.

3441016553981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 50.

The spelling of 3441016553981 in words is "three trillion, four hundred forty-one billion, sixteen million, five hundred fifty-three thousand, nine hundred eighty-one".