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344115403412117 is a prime number
BaseRepresentation
bin100111000111110001001110…
…0011000011101001010010101
31200010102010000010110001102112
41032033202130120131022111
5330100441321233141432
63215512233422120405
7132324342326420411
oct11617423430351225
91603363003401375
10344115403412117
119a711583179817
1232717a54420105
1311a01c3558b17c
1460d93bad07d41
1529bb370bbe7b2
hex138f89c61d295

344115403412117 has 2 divisors, whose sum is σ = 344115403412118. Its totient is φ = 344115403412116.

The previous prime is 344115403412113. The next prime is 344115403412173. The reversal of 344115403412117 is 711214304511443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 266853166880881 + 77262236531236 = 16335641^2 + 8789894^2 .

It is a cyclic number.

It is not a de Polignac number, because 344115403412117 - 22 = 344115403412113 is a prime.

It is a super-2 number, since 2×3441154034121172 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (344115403412113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172057701706058 + 172057701706059.

It is an arithmetic number, because the mean of its divisors is an integer number (172057701706059).

Almost surely, 2344115403412117 is an apocalyptic number.

It is an amenable number.

344115403412117 is a deficient number, since it is larger than the sum of its proper divisors (1).

344115403412117 is an equidigital number, since it uses as much as digits as its factorization.

344115403412117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 161280, while the sum is 41.

The spelling of 344115403412117 in words is "three hundred forty-four trillion, one hundred fifteen billion, four hundred three million, four hundred twelve thousand, one hundred seventeen".