Base | Representation |
---|---|
bin | 100000000011001011… |
… | …101011101011111101 |
3 | 10021211022101021010111 |
4 | 200003023223223331 |
5 | 1030434230220131 |
6 | 23450440510021 |
7 | 2325534541324 |
oct | 400313535375 |
9 | 107738337114 |
10 | 34413132541 |
11 | 1365a352907 |
12 | 6804a7b311 |
13 | 3325775728 |
14 | 19465c10bb |
15 | d662a8ab1 |
hex | 8032ebafd |
34413132541 has 2 divisors, whose sum is σ = 34413132542. Its totient is φ = 34413132540.
The previous prime is 34413132503. The next prime is 34413132563. The reversal of 34413132541 is 14523131443.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34384284900 + 28847641 = 185430^2 + 5371^2 .
It is a cyclic number.
It is not a de Polignac number, because 34413132541 - 221 = 34411035389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34413132571) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17206566270 + 17206566271.
It is an arithmetic number, because the mean of its divisors is an integer number (17206566271).
Almost surely, 234413132541 is an apocalyptic number.
It is an amenable number.
34413132541 is a deficient number, since it is larger than the sum of its proper divisors (1).
34413132541 is an equidigital number, since it uses as much as digits as its factorization.
34413132541 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17280, while the sum is 31.
Adding to 34413132541 its reverse (14523131443), we get a palindrome (48936263984).
The spelling of 34413132541 in words is "thirty-four billion, four hundred thirteen million, one hundred thirty-two thousand, five hundred forty-one".
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