Base | Representation |
---|---|
bin | 1111101001110000010010… |
… | …01011110100100110011111 |
3 | 11111212112002111220000122111 |
4 | 13310320021023310212133 |
5 | 14002414201113113002 |
6 | 201112201222254451 |
7 | 10151523142464244 |
oct | 764701113644637 |
9 | 144775074800574 |
10 | 34420022004127 |
11 | aa704a4103071 |
12 | 3a3a9b7887427 |
13 | 1628a42986326 |
14 | 86dd1ba615cb |
15 | 3ea5252e33d7 |
hex | 1f4e092f499f |
34420022004127 has 2 divisors, whose sum is σ = 34420022004128. Its totient is φ = 34420022004126.
The previous prime is 34420022004089. The next prime is 34420022004131. The reversal of 34420022004127 is 72140022002443.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34420022004127 - 215 = 34420021971359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34420022014127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17210011002063 + 17210011002064.
It is an arithmetic number, because the mean of its divisors is an integer number (17210011002064).
Almost surely, 234420022004127 is an apocalyptic number.
34420022004127 is a deficient number, since it is larger than the sum of its proper divisors (1).
34420022004127 is an equidigital number, since it uses as much as digits as its factorization.
34420022004127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 31.
The spelling of 34420022004127 in words is "thirty-four trillion, four hundred twenty billion, twenty-two million, four thousand, one hundred twenty-seven".
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