Base | Representation |
---|---|
bin | 110010000101101000100… |
… | …101011000000011011101 |
3 | 110012001110112100012101122 |
4 | 302011220211120003131 |
5 | 422343230444314123 |
6 | 11153124351420325 |
7 | 503451356303546 |
oct | 62055045300335 |
9 | 13161415305348 |
10 | 3442023432413 |
11 | 1107832548905 |
12 | 4771068246a5 |
13 | 1bc7734b0687 |
14 | bc8482a14cd |
15 | 5e8055b4bc8 |
hex | 321689580dd |
3442023432413 has 2 divisors, whose sum is σ = 3442023432414. Its totient is φ = 3442023432412.
The previous prime is 3442023432401. The next prime is 3442023432439. The reversal of 3442023432413 is 3142343202443.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2768223784804 + 673799647609 = 1663798^2 + 820853^2 .
It is a cyclic number.
It is not a de Polignac number, because 3442023432413 - 28 = 3442023432157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3442023432443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1721011716206 + 1721011716207.
It is an arithmetic number, because the mean of its divisors is an integer number (1721011716207).
Almost surely, 23442023432413 is an apocalyptic number.
It is an amenable number.
3442023432413 is a deficient number, since it is larger than the sum of its proper divisors (1).
3442023432413 is an equidigital number, since it uses as much as digits as its factorization.
3442023432413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 3442023432413 its reverse (3142343202443), we get a palindrome (6584366634856).
The spelling of 3442023432413 in words is "three trillion, four hundred forty-two billion, twenty-three million, four hundred thirty-two thousand, four hundred thirteen".
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