Base | Representation |
---|---|
bin | 110010000101101101110… |
… | …111001111011110110011 |
3 | 110012001200200222222222122 |
4 | 302011231313033132303 |
5 | 422343421133030341 |
6 | 11153141234024455 |
7 | 503453513161046 |
oct | 62055567173663 |
9 | 13161620888878 |
10 | 3442112001971 |
11 | 1107878542495 |
12 | 47713041812b |
13 | 1bc7889514b6 |
14 | bc855d58c5d |
15 | 5e80d25c94b |
hex | 3216ddcf7b3 |
3442112001971 has 2 divisors, whose sum is σ = 3442112001972. Its totient is φ = 3442112001970.
The previous prime is 3442112001953. The next prime is 3442112001973. The reversal of 3442112001971 is 1791002112443.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3442112001971 - 218 = 3442111739827 is a prime.
It is a super-2 number, since 2×34421120019712 (a number of 26 digits) contains 22 as substring.
Together with 3442112001973, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3442112001973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1721056000985 + 1721056000986.
It is an arithmetic number, because the mean of its divisors is an integer number (1721056000986).
Almost surely, 23442112001971 is an apocalyptic number.
3442112001971 is a deficient number, since it is larger than the sum of its proper divisors (1).
3442112001971 is an equidigital number, since it uses as much as digits as its factorization.
3442112001971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 35.
The spelling of 3442112001971 in words is "three trillion, four hundred forty-two billion, one hundred twelve million, one thousand, nine hundred seventy-one".
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