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34424343401051 is a prime number
BaseRepresentation
bin1111101001111000010101…
…10000101001001001011011
311111212221020200100201210102
413310330022300221021123
514003002023402313201
6201114154113010015
710152035214655142
oct764741260511133
9144787220321712
1034424343401051
11aa7231145558a
123a3b802b5390b
131629281057a26
1487020b958759
153ea6c98a226b
hex1f4f0ac2925b

34424343401051 has 2 divisors, whose sum is σ = 34424343401052. Its totient is φ = 34424343401050.

The previous prime is 34424343401039. The next prime is 34424343401141. The reversal of 34424343401051 is 15010434342443.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 34424343401051 - 226 = 34424276292187 is a prime.

It is a super-3 number, since 3×344243434010513 (a number of 42 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34424343400996 and 34424343401014.

It is not a weakly prime, because it can be changed into another prime (34424345401051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17212171700525 + 17212171700526.

It is an arithmetic number, because the mean of its divisors is an integer number (17212171700526).

Almost surely, 234424343401051 is an apocalyptic number.

34424343401051 is a deficient number, since it is larger than the sum of its proper divisors (1).

34424343401051 is an equidigital number, since it uses as much as digits as its factorization.

34424343401051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 276480, while the sum is 38.

Adding to 34424343401051 its reverse (15010434342443), we get a palindrome (49434777743494).

The spelling of 34424343401051 in words is "thirty-four trillion, four hundred twenty-four billion, three hundred forty-three million, four hundred one thousand, fifty-one".