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34432331413 is a prime number
BaseRepresentation
bin100000000100010100…
…111010111010010101
310021212122111200000211
4200010110322322111
51031004134101123
623452404205421
72326156662604
oct400424727225
9107778450024
1034432331413
111366a176247
12680b399871
1333297382cc
141948d7ba3b
15d67cec40d
hex80453ae95

34432331413 has 2 divisors, whose sum is σ = 34432331414. Its totient is φ = 34432331412.

The previous prime is 34432331371. The next prime is 34432331467. The reversal of 34432331413 is 31413323443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25189816369 + 9242515044 = 158713^2 + 96138^2 .

It is an emirp because it is prime and its reverse (31413323443) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34432331413 - 213 = 34432323221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34432331513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17216165706 + 17216165707.

It is an arithmetic number, because the mean of its divisors is an integer number (17216165707).

Almost surely, 234432331413 is an apocalyptic number.

It is an amenable number.

34432331413 is a deficient number, since it is larger than the sum of its proper divisors (1).

34432331413 is an equidigital number, since it uses as much as digits as its factorization.

34432331413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 31.

Adding to 34432331413 its reverse (31413323443), we get a palindrome (65845654856).

The spelling of 34432331413 in words is "thirty-four billion, four hundred thirty-two million, three hundred thirty-one thousand, four hundred thirteen".