Base | Representation |
---|---|
bin | 1010000001010111011… |
… | …10111111110111101001 |
3 | 1012220210000202110201001 |
4 | 11000223232333313221 |
5 | 21120142231433301 |
6 | 422103350555001 |
7 | 33606563156401 |
oct | 5005356776751 |
9 | 1186700673631 |
10 | 344331124201 |
11 | 123036a41029 |
12 | 56897968a61 |
13 | 266162aa24c |
14 | 12946a19801 |
15 | 8e54526c01 |
hex | 502bbbfde9 |
344331124201 has 2 divisors, whose sum is σ = 344331124202. Its totient is φ = 344331124200.
The previous prime is 344331124133. The next prime is 344331124211. The reversal of 344331124201 is 102421133443.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 344306074176 + 25050025 = 586776^2 + 5005^2 .
It is a cyclic number.
It is not a de Polignac number, because 344331124201 - 213 = 344331116009 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 344331124201.
It is not a weakly prime, because it can be changed into another prime (344331124211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172165562100 + 172165562101.
It is an arithmetic number, because the mean of its divisors is an integer number (172165562101).
Almost surely, 2344331124201 is an apocalyptic number.
It is an amenable number.
344331124201 is a deficient number, since it is larger than the sum of its proper divisors (1).
344331124201 is an equidigital number, since it uses as much as digits as its factorization.
344331124201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 344331124201 its reverse (102421133443), we get a palindrome (446752257644).
The spelling of 344331124201 in words is "three hundred forty-four billion, three hundred thirty-one million, one hundred twenty-four thousand, two hundred one".
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