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344401339993 is a prime number
BaseRepresentation
bin1010000001011111110…
…10110110011001011001
31012220221220212210122221
411000233322312121121
521120313220334433
6422114335544041
733611405042224
oct5005772663131
91186856783587
10344401339993
1112307263a207
12568b738b021
13266279c3059
14129520965bb
158e5a79672d
hex502feb6659

344401339993 has 2 divisors, whose sum is σ = 344401339994. Its totient is φ = 344401339992.

The previous prime is 344401339979. The next prime is 344401340011. The reversal of 344401339993 is 399933104443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 272747151504 + 71654188489 = 522252^2 + 267683^2 .

It is a cyclic number.

It is not a de Polignac number, because 344401339993 - 213 = 344401331801 is a prime.

It is a super-2 number, since 2×3444013399932 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 344401339993.

It is not a weakly prime, because it can be changed into another prime (344401339903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172200669996 + 172200669997.

It is an arithmetic number, because the mean of its divisors is an integer number (172200669997).

Almost surely, 2344401339993 is an apocalyptic number.

It is an amenable number.

344401339993 is a deficient number, since it is larger than the sum of its proper divisors (1).

344401339993 is an equidigital number, since it uses as much as digits as its factorization.

344401339993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3779136, while the sum is 52.

The spelling of 344401339993 in words is "three hundred forty-four billion, four hundred one million, three hundred thirty-nine thousand, nine hundred ninety-three".