Base | Representation |
---|---|
bin | 1010000001011111110… |
… | …10110110011001101011 |
3 | 1012220221220212210200121 |
4 | 11000233322312121223 |
5 | 21120313220340021 |
6 | 422114335544111 |
7 | 33611405042251 |
oct | 5005772663153 |
9 | 1186856783617 |
10 | 344401340011 |
11 | 12307263a223 |
12 | 568b738b037 |
13 | 266279c3071 |
14 | 129520965d1 |
15 | 8e5a796741 |
hex | 502feb666b |
344401340011 has 2 divisors, whose sum is σ = 344401340012. Its totient is φ = 344401340010.
The previous prime is 344401339993. The next prime is 344401340051. The reversal of 344401340011 is 110043104443.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 344401340011 - 25 = 344401339979 is a prime.
It is a super-2 number, since 2×3444013400112 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (344401340051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172200670005 + 172200670006.
It is an arithmetic number, because the mean of its divisors is an integer number (172200670006).
Almost surely, 2344401340011 is an apocalyptic number.
344401340011 is a deficient number, since it is larger than the sum of its proper divisors (1).
344401340011 is an equidigital number, since it uses as much as digits as its factorization.
344401340011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 344401340011 its reverse (110043104443), we get a palindrome (454444444454).
The spelling of 344401340011 in words is "three hundred forty-four billion, four hundred one million, three hundred forty thousand, eleven".
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