344401430053 has 2 divisors, whose sum is σ = 344401430054. Its totient is φ = 344401430052.

The previous prime is 344401430041. The next prime is 344401430089. The reversal of 344401430053 is 350034104443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 332182780609 + 12218649444 = 576353^2 + 110538^2 .

It is an emirp because it is prime and its reverse (350034104443) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-344401430053 is a prime.

It is a super-4 number, since 4×344401430053⁴ (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 344401429997 and 344401430024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (344401430953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172200715026 + 172200715027.

It is an arithmetic number, because the mean of its divisors is an integer number (172200715027).

Almost surely, 2^344401430053 is an apocalyptic number.

It is an amenable number.

344401430053 is a deficient number, since it is larger than the sum of its proper divisors (1).

344401430053 is an equidigital number, since it uses as much as digits as its factorization.

344401430053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 344401430053 its reverse (350034104443), we get a palindrome (694435534496).

The spelling of 344401430053 in words is "three hundred forty-four billion, four hundred one million, four hundred thirty thousand, fifty-three".