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3444017313949 is a prime number
BaseRepresentation
bin110010000111011111011…
…011011011100010011101
3110012020121111011212122221
4302013133123123202131
5422411321413021244
611154054255305341
7503551650103342
oct62073733334235
913166544155587
103444017313949
111108665a96593
1247758251b251
131bca005c4b34
14bc9970067c9
155e8c0669784
hex321df6db89d

3444017313949 has 2 divisors, whose sum is σ = 3444017313950. Its totient is φ = 3444017313948.

The previous prime is 3444017313943. The next prime is 3444017313953. The reversal of 3444017313949 is 9493137104443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3423961656025 + 20055657924 = 1850395^2 + 141618^2 .

It is a cyclic number.

It is not a de Polignac number, because 3444017313949 - 241 = 1244994058397 is a prime.

It is a super-2 number, since 2×34440173139492 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3444017313896 and 3444017313905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3444017313943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1722008656974 + 1722008656975.

It is an arithmetic number, because the mean of its divisors is an integer number (1722008656975).

Almost surely, 23444017313949 is an apocalyptic number.

It is an amenable number.

3444017313949 is a deficient number, since it is larger than the sum of its proper divisors (1).

3444017313949 is an equidigital number, since it uses as much as digits as its factorization.

3444017313949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3919104, while the sum is 52.

The spelling of 3444017313949 in words is "three trillion, four hundred forty-four billion, seventeen million, three hundred thirteen thousand, nine hundred forty-nine".