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34445502031541 is a prime number
BaseRepresentation
bin1111101010011111101111…
…11010011010011010110101
311111221221212021001112021112
413311033313322122122311
514003323342010002131
6201132013431524405
710153414436236406
oct765176772323265
9144857767045245
1034445502031541
11aa802899a4867
123a43928b29705
13162b2737a0b23
14871257a819ad
153eb0171d602b
hex1f53f7e9a6b5

34445502031541 has 2 divisors, whose sum is σ = 34445502031542. Its totient is φ = 34445502031540.

The previous prime is 34445502031519. The next prime is 34445502031601. The reversal of 34445502031541 is 14513020554443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34314406622500 + 131095409041 = 5857850^2 + 362071^2 .

It is a cyclic number.

It is not a de Polignac number, because 34445502031541 - 26 = 34445502031477 is a prime.

It is a super-2 number, since 2×344455020315412 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34445508031541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17222751015770 + 17222751015771.

It is an arithmetic number, because the mean of its divisors is an integer number (17222751015771).

Almost surely, 234445502031541 is an apocalyptic number.

It is an amenable number.

34445502031541 is a deficient number, since it is larger than the sum of its proper divisors (1).

34445502031541 is an equidigital number, since it uses as much as digits as its factorization.

34445502031541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576000, while the sum is 41.

Adding to 34445502031541 its reverse (14513020554443), we get a palindrome (48958522585984).

The spelling of 34445502031541 in words is "thirty-four trillion, four hundred forty-five billion, five hundred two million, thirty-one thousand, five hundred forty-one".