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3445110000131 is a prime number
BaseRepresentation
bin110010001000100000100…
…011101100101000000011
3110012100102122021002022112
4302020200203230220003
5422421041130001011
611154354531325535
7503621015555342
oct62104043545003
913170378232275
103445110000131
111109076865918
124778284508ab
131bcb45ab47c7
14bca5c19db59
155e93655858b
hex322208eca03

3445110000131 has 2 divisors, whose sum is σ = 3445110000132. Its totient is φ = 3445110000130.

The previous prime is 3445109999957. The next prime is 3445110000139. The reversal of 3445110000131 is 1310000115443.

It is a happy number.

3445110000131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3445110000131 is a prime.

It is a super-2 number, since 2×34451100001312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3445110000097 and 3445110000106.

It is not a weakly prime, because it can be changed into another prime (3445110000139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1722555000065 + 1722555000066.

It is an arithmetic number, because the mean of its divisors is an integer number (1722555000066).

Almost surely, 23445110000131 is an apocalyptic number.

3445110000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3445110000131 is an equidigital number, since it uses as much as digits as its factorization.

3445110000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 3445110000131 its reverse (1310000115443), we get a palindrome (4755110115574).

The spelling of 3445110000131 in words is "three trillion, four hundred forty-five billion, one hundred ten million, one hundred thirty-one", and thus it is an aban number.