Base | Representation |
---|---|
bin | 100000001000100110… |
… | …100001001010011001 |
3 | 10022001122110112002202 |
4 | 200020212201022121 |
5 | 1031131014202101 |
6 | 23503445335545 |
7 | 2331020420606 |
oct | 401046411231 |
9 | 108048415082 |
10 | 34504053401 |
11 | 136a6703014 |
12 | 682b4075b5 |
13 | 333b55a85c |
14 | 19546cb6ad |
15 | d6e26836b |
hex | 8089a1299 |
34504053401 has 2 divisors, whose sum is σ = 34504053402. Its totient is φ = 34504053400.
The previous prime is 34504053379. The next prime is 34504053403. The reversal of 34504053401 is 10435040543.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30783053401 + 3721000000 = 175451^2 + 61000^2 .
It is a cyclic number.
It is not a de Polignac number, because 34504053401 - 234 = 17324184217 is a prime.
Together with 34504053403, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (34504053403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17252026700 + 17252026701.
It is an arithmetic number, because the mean of its divisors is an integer number (17252026701).
Almost surely, 234504053401 is an apocalyptic number.
It is an amenable number.
34504053401 is a deficient number, since it is larger than the sum of its proper divisors (1).
34504053401 is an equidigital number, since it uses as much as digits as its factorization.
34504053401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 34504053401 its reverse (10435040543), we get a palindrome (44939093944).
The spelling of 34504053401 in words is "thirty-four billion, five hundred four million, fifty-three thousand, four hundred one".
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