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34505025133 is a prime number
BaseRepresentation
bin100000001000101010…
…001110011001101101
310022001201021220001211
4200020222032121231
51031131241301013
623503522234421
72331031605625
oct401052163155
9108051256054
1034505025133
11136a72070a7
12682b7b5a11
13333b80ac47
1419548a1885
15d6e3ab23d
hex808a8e66d

34505025133 has 2 divisors, whose sum is σ = 34505025134. Its totient is φ = 34505025132.

The previous prime is 34505025119. The next prime is 34505025157. The reversal of 34505025133 is 33152050543.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23035043529 + 11469981604 = 151773^2 + 107098^2 .

It is an emirp because it is prime and its reverse (33152050543) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34505025133 - 25 = 34505025101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34505025095 and 34505025104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34505025193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17252512566 + 17252512567.

It is an arithmetic number, because the mean of its divisors is an integer number (17252512567).

Almost surely, 234505025133 is an apocalyptic number.

It is an amenable number.

34505025133 is a deficient number, since it is larger than the sum of its proper divisors (1).

34505025133 is an equidigital number, since it uses as much as digits as its factorization.

34505025133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 31.

Adding to 34505025133 its reverse (33152050543), we get a palindrome (67657075676).

The spelling of 34505025133 in words is "thirty-four billion, five hundred five million, twenty-five thousand, one hundred thirty-three".