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345100413613 is a prime number
BaseRepresentation
bin1010000010110011001…
…01100110101010101101
31012222202122022102101111
411001121211212222231
521123231201213423
6422311551312021
733634624054564
oct5013145465255
91188678272344
10345100413613
111233a12065aa
1256a7151b611
1326709799897
14129bac6cbdb
158e9bd3460d
hex5059966aad

345100413613 has 2 divisors, whose sum is σ = 345100413614. Its totient is φ = 345100413612.

The previous prime is 345100413583. The next prime is 345100413629. The reversal of 345100413613 is 316314001543.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 250717514089 + 94382899524 = 500717^2 + 307218^2 .

It is an emirp because it is prime and its reverse (316314001543) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 345100413613 - 213 = 345100405421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (345100413113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172550206806 + 172550206807.

It is an arithmetic number, because the mean of its divisors is an integer number (172550206807).

Almost surely, 2345100413613 is an apocalyptic number.

It is an amenable number.

345100413613 is a deficient number, since it is larger than the sum of its proper divisors (1).

345100413613 is an equidigital number, since it uses as much as digits as its factorization.

345100413613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 31.

The spelling of 345100413613 in words is "three hundred forty-five billion, one hundred million, four hundred thirteen thousand, six hundred thirteen".